How much vertical load can a beam 150 withstand. Calculation of the bearing capacity and deflection of wooden beams

The main condition for any construction is the simplicity and reliability of the design, but in order to achieve this, it is necessary to make the correct calculations of the strength of the material. Since a wooden frame is used for the construction of wooden houses, an attic or an attic, its choice must be approached with all responsibility, because durability, reliability and stability will directly depend on what load the beam can withstand (100x100, 50x50, 150x150, etc.) built house.

For the correct calculation of the load withstood by the beam, special programs or formulas can be used, but in this case, additional loads will have to be introduced into the calculations, which directly affect the strength of the structure. In order to calculate the load on the beam correctly, you will have to indicate the snow and wind effects that are present directly in the building region, as well as the characteristics of the materials used (heat isover, beam, etc.).

In this article, we will consider what kind of load a beam with a size of 50x50, 100x100, 150x150 can withstand in various structures, such as a timber house, a wooden floor and a truss system, and as an example, we will analyze the latter, because this is the most responsible and difficult work.

In the photo you can see the varieties of timber, which differ not only in shape, but also in the load capacity.

What will be discussed:

How does the cross-section of a log house affect its reliability?

When creating a roof, a prerequisite for its reliability is the cross section of the timber used and the type of wood, which affects durability.

Performing the calculation with your own hands, you will need to take into account such indicators as:

• what is the mass of all roofing building materials;
• the weight of the attic or attic finish;
• for rafter supports and beams, the calculated value is taken into account;
• the thermal and sedimentary effects of nature are taken into account.

In addition, you will need to specify:

• distance between beams;
• the length of the gap between the rafter supports;
• the principle of fastening the rafters and the configuration of its truss;
• the severity of precipitation and the effect of winds on the structure;
• other factors that may affect the reliability of the design.

All these calculations can be done manually using special formulas. But it will be simpler both in terms of time and quality to calculate the load of the beam using special programs, and even better when these calculations are performed by a professional.

What requirements must the beam meet?

In order for the entire rafter system to be strong and reliable, the quality of building materials will have to be approached with all responsibility. For example, there should be no defects on the beam (cracks, knots, etc.), and its moisture content should not exceed 20%. In addition, a log house of any size (50x50, 100x100, 150x150, etc.) must be treated with protective agents against shashel and other insects, rotting and fire.

Also, when choosing a material, you will have to take into account that additional loads may be applied to the timber, such as:

• Continuous load beam. These include directly the weight of the entire truss system, which includes: facing and roofing materials, insulation, etc. The data obtained for each material are summarized.
• Short-term loads can be of several types: especially rare, short-term and long-term effects. The first type includes incidents that happen very rarely (earthquakes, floods, etc.). Wind and snow impacts, the movement of people repairing the roof, etc. are short-lived. All other impacts that occur within a certain period of time are long-term loads.

We determine the wind and snow load on the beam

To determine what load the beam can withstand (100x100, 150x150.50x50, etc.) under wind and snow exposure, you can use certain tables.

To determine the snow effect on rafters of different sections, the formula S \u003d Sg * µ is used.

• Sg - is the calculated weight of snow lying on the ground, which affects 1 m².

Important! This value cannot be compared with the roof load.

• µ is the value of the load on the roof surface, which varies from horizontal to sloping. This coefficient can take on different values, it all depends on the slope of the roof.

With a surface slope of up to 25 degrees, µ takes on the value 1.

When the slope of the roof is in the range of 25-60 degrees, µ is 0.7.

With a slope of 60 degrees or more, the coefficient µ is not taken into account because it practically does not affect the truss system.

In addition to the snow load, before the construction of the truss system, the wind load on the wooden beam is calculated 50 by 50, 100x100, etc. If these indicators are not taken into account, as a result, everything can end in failure. Table values ​​and the formula W=Wo*k are used for the calculation.

Wo - is a tabular value of the wind load for each individual region.

k is the wind pressure, which has different meanings as altitude changes. These indicators are also tabular.

The table of beam loads shown in the photo when exposed to the elements is easy to use, you just need to remember that the 1st column shows the values ​​\u200b\u200bfor the steppe, desert regions, rivers, lakes, forest-steppe, tundra, seashores and reservoirs. The next column contains data related to urban areas and areas with 10 meter obstacles.

Important! In calculations, it is desirable to use information on the direction of wind movement, because this can make an important correction to the results.

By what rules is the desired cross section of the beam calculated?

Several parameters influence the selection of the log section for the truss system:

• what is the length of the rafter construction;
• the distance between each subsequent beam;
• the results of load calculations for the corresponding area.

Today, for each specific area, there are special tables with data already entered on the load values ​​\u200b\u200bfor truss systems. An example is the Moscow region:

• in order to install a Mauerlat, you can use a bar with a section of at least 100x100, 150x100 and 150x150;
• timber 200x100 can be used for diagonal valleys and rafter supports (legs);
• runs can be created from wood 100x100, 150x100 or 200x100;
• a log house 150x50 will be the best solution for tightening;
• it is best to use a log house 150x150 or 100x100 as racks;
• a 150x50 rafter is suitable for a cornice, struts or filly;
• crossbars are best installed from rafters 150x100 or 200x100;
• As a sheathing or frontal, you can use a board of at least 22x100.

The above data are optimal, that is, less than this value, the material cannot be used. Also, all dimensions are in millimeters.

Summarize

To create a reliable and durable wooden structure, you need to carefully calculate all possible loads, after which you only need to purchase timber. If you have doubts about the correctness of the calculations, it is best to use the services of a professional or use a special program that will calculate the allowable load on the timber (150x150, 100x100, etc.).

The possibility of unsupported overlapping of large areas greatly expands the architectural possibilities when designing a house. A positive solution to the beam issue allows you to "play" with the volume of rooms, install panoramic windows, build large halls. But if it is not difficult to block a distance of 3-4 meters with a “tree”, then which beams to use on a span of 5 m or more is already a difficult question.

Wooden floor beams - dimensions and loads

They made a wooden floor in a log house, and the floor is shaking, bending, the effect of a “trampoline” has appeared; we want to make wooden floor beams of 7 meters; you need to block the room with a length of 6.8 meters so as not to rest the logs on intermediate supports; what should be the floor beam for a span of 6 meters, a house made of timber; what to do if you want to make a free layout - such questions are often asked by members of the forum.

Maxinova FORUMHOUSE user

My house is about 10x10 meters. I “threw” wooden logs onto the ceiling, their length is 5 meters, the section is 200x50. The distance between the lags is 60 cm. During the operation of the floor, it turned out that when children run in one room and you stand in another, there is quite a strong vibration on the floor.

And this case is far from the only one.

elena555 FORUMHOUSE user

I can’t figure out which beams for interfloor ceilings are needed. My house is 12x12 meters, 2-storey. The first floor is made of aerated concrete, the second floor is attic, wooden, covered with a bar 6000x150x200mm, laid every 80 cm. When I walk on the second floor, I feel shaking.

Beams for long spans must withstand heavy loads, therefore, in order to build a strong and reliable wooden floor with a large span, they must be carefully calculated. First of all, it is necessary to understand what kind of load a wooden log of one or another section can withstand. And then think over, having determined the load for the floor beam, what kind of rough and finish flooring will need to be done; what will the ceiling be hemmed with; whether the floor will be a full-fledged living space or a non-residential attic above the garage.

Leo060147 FORUMHOUSE user

1. The load from the own weight of all structural elements of the floor. This includes the weight of beams, insulation, fasteners, flooring, ceiling, etc.
2. operating load. The operating load can be permanent or temporary.

When calculating the operating load, the mass of people, furniture, household appliances, etc. is taken into account. The load temporarily increases with the arrival of guests, noisy celebrations, rearrangement of furniture, if it is moved away from the walls to the center of the room.

Therefore, when calculating the operational load, it is necessary to think through everything - up to what kind of furniture is planned to be installed, and whether there is a possibility of installing a sports simulator in the future, which also weighs far more than one kilogram.

For the load acting on wooden beams of a long floor, the following values ​​\u200b\u200bare taken (for attic and interfloor floors):

• Attic floor - 150 kg / sq.m. Where (according to SNiP 2.01.07-85), taking into account the safety factor - 50 kg / sq.m - this is the load from the floor's own weight, and 100 kg / sq.m - the standard load.

If it is planned to store things, materials and other household items in the attic, then the load is assumed to be 250 kg / sq.m.

• For interfloor floors and ceilings of the attic floor, the total load is taken at the rate of 350-400 kg / sq.m.

Overlapping boards 200 by 50 and other running sizes

These are the beams on a span of 4 meters that are allowed by the regulations.

Most often, in the construction of wooden floors, boards and timber of the so-called running sizes are used: 50x150, 50x200, 100x150, etc. Such beams satisfy the standards ( after calculation), if it is planned to block the opening no more than four meters.

For overlapping with a length of 6 meters or more, the dimensions 50x150, 50x200, 100x150 are no longer suitable.

Wooden beam over 6 meters: subtleties

A beam for a span of 6 meters or more should not be made of timber and boards of running sizes.

You should remember the rule: the strength and rigidity of the floor to a greater extent depend on the height of the beam and, to a lesser extent, on its width.

A distributed and concentrated load acts on the floor beam. Therefore, wooden beams for large spans are not designed "end-to-end", but with a margin of strength and allowable deflection. This ensures normal and safe operation of the ceiling.

50x200 - overlap for an opening of 4 and 5 meters.

To calculate the load that the overlap will withstand, you must have the appropriate knowledge. In order not to delve into the strength of materials formulas (and this is definitely redundant when building a garage), it is enough for an ordinary developer to use online calculators for calculating wooden single-span beams.

Leo060147 FORUMHOUSE user

A self-builder is most often not a professional designer. All he wants to know is which beams need to be installed in the ceiling so that it meets the basic requirements for strength and reliability. This is what online calculators allow you to calculate.

These calculators are easy to use. To make calculations of the necessary values, it is enough to enter the dimensions of the lag and the length of the span, which they must cover.

Also, to simplify the task, you can use ready-made tables presented by the gurus of our forum with the nickname Roracotta.

Roracotta FORUMHOUSE user

I spent several evenings to make tables that even a novice builder will understand:

Table 1. It presents data that meet the minimum load requirements for the floors of the second floor - 147kg / sq.m.

Note: since the tables are based on American standards, and the dimensions of lumber overseas are somewhat different from the sections adopted in our country, the column highlighted in yellow should be used in the calculations.

Table 2. Here are the data on the average load for the floors of the first and second floors - 293 kg / sq.m.

Table 3. Here are the data for the calculated increased load of 365 kg / sq.m.

How to calculate the distance between I-beams

If you carefully read the tables presented above, it becomes clear that with an increase in the length of the span, first of all, it is necessary to increase the height of the log, and not its width.

Leo060147 FORUMHOUSE user

You can change the stiffness and strength of the lag upwards by increasing its height and making “shelves”. That is, a wooden I-beam is being made.

Independent production of a wooden glued beam

One solution for long span spans is the use of timber beams in the spans. Consider a span of 6 meters - which beams can withstand a large load.

According to the type of cross section, a long beam can be:

• rectangular;
• I-beam;
• box-shaped.

There is no consensus among self-builders which section is better. If you do not take into account purchased products (prefabricated I-beams), then the simplicity of manufacturing in the "field conditions" comes first, without the use of expensive equipment and tooling.

Just Grandpa FORUMHOUSE user

If you look at the cross section of any metal I-beam, you can see that from 85% to 90% of the mass of the metal is concentrated in the "shelves". The bonding wall accounts for no more than 10-15% of the metal. This is done on the basis of calculation.

What board to use for beams

According to the strength of materials: the larger the section of the “shelves” and the further they are spaced from each other in height, the greater the load the I-beam will withstand. For a self-builder, the optimal technology for manufacturing an I-beam is a simple box-shaped design, where the upper and lower "shelves" are made of a board laid flat. (50x150mm, and the side walls are made of plywood with a thickness of 8-12 mm and a height of 350 to 400 mm (determined by calculation), etc.).

Plywood is nailed to the shelves or screwed with self-tapping screws (only not black, they do not cut) and must be glued.

If you install such an I-beam on a six-meter span in increments of 60 cm, then it will withstand a large load. Additionally, an I-beam for a ceiling of 6 meters can be laid with a heater.

Also, using a similar principle, you can connect two long boards, assembling them into a “package”, and then put them on top of each other on an edge (take boards at 150x50 or 200x50), as a result, the cross section of the beam will be 300x100 or 400x100 mm. The boards are planted on glue and pulled together with studs or planted on capercaillie / dowels. You can also screw or nail plywood to the side surfaces of such a beam, having previously lubricated it with glue.

Also interesting is the experience of a forum member under the nickname Taras174, who decided to independently make a glued I-beam to block a span of 8 meters.

For this, the forum member purchased OSB sheets 12 mm thick, cut them lengthwise into five equal parts. Then I bought a board 150x50 mm, 8 meters long. With a dovetail cutter, I chose a groove in the middle of the board with a depth of 12 mm and a width of 14 mm - so that a trapezoid with an extension downwards was obtained. OSB in grooves Taras174 glued with the help of polyester resin (epoxy), having previously “shooted” a strip of fiberglass 5 mm wide to the end of the plate with a stapler. This, according to the forum member, would strengthen the design. To speed up drying, the glued area was heated with a heater.

Taras174 FORUMHOUSE user

On the first beam, I trained "filled my hand." The second one was done in 1 business day. At a cost, taking into account all materials, I include a solid board of 8 meters, the cost of a beam is 2000 rubles. for 1 piece

Despite the positive experience, such a "squatter" did not escape several criticisms made by our experts. Namely.

The beams in the house usually belong to the rafter system or ceiling, and in order to obtain a reliable structure, the operation of which can be carried out without any fear, it is necessary to use beam calculator.

What is the beam calculator based on

When the walls are already brought under the second floor or under the roof, it is necessary to make, in the second case, smoothly turning into rafter legs. At the same time, the materials must be selected so that the load on the brick or log walls does not exceed the permissible level, and the strength of the structure is at the proper level. Therefore, if you are going to use wood, you need to choose the right beams from it, make calculations to find out the desired thickness and sufficient length.

Sagging or partial destruction of the floor can be caused by various reasons, for example, too large a step between the lags, deflection of the crossbars, too small a cross-sectional area or defects in the structure. To exclude possible excesses, you should find out the estimated load on the floor, whether it is basement or interfloor, after which we use the beam calculator, taking into account their own mass. The latter can vary in concrete lintels, the weight of which depends on the density of reinforcement; for wood and metal, with a certain geometry, the mass is constant. An exception is damp wood, which is not used in construction work without prior drying.

Beam systems in ceilings and truss structures are loaded by forces acting on the bending of the section, on torsion, on deflection along the length. For rafters, it is also necessary to provide for snow and wind loads, which also create certain forces applied to the beams. It is also necessary to accurately determine the required step between the jumpers, since too many crossbars will lead to an extra mass of the floor (or roof), and too little, as mentioned above, will weaken the structure.

You may also be interested in the article on calculating the number of unedged and edged boards in a cube:

How to calculate the load on the floor beam

The distance between the walls is called a span, and there are two of them in a room, and one span will necessarily be smaller than the other if the shape of the room is not square. Lintels of an interfloor or attic floor should be laid along a shorter span, the optimal length of which is from 3 to 4 meters. Larger spacings may require non-standard sized beams, resulting in some swaying in the deck. The best way out in this case would be to use metal crossbars.

As for the cross section of a wooden beam, there is a certain standard that requires that the sides of the beam be in a ratio of 7: 5, that is, the height is divided into 7 parts, and 5 of them should make up the width of the profile. In this case, the deformation of the section is excluded, but if you deviate from the above indicators, then with a width exceeding the height, you will get a deflection, or, in case of a reverse discrepancy, a bend to the side. To prevent this from happening due to the excessive length of the beam, you need to know how to calculate the load on the beam. In particular, the allowable deflection is calculated from the ratio to the length of the jumper, as 1:200, that is, it should be 2 centimeters by 4 meters.

So that the beam does not sag under the weight of the lags and flooring, as well as interior items, you can carve it from the bottom by several centimeters, giving it the shape of an arch, in which case its height should have an appropriate margin.

Now let's turn to the formulas. The same deflection, which was mentioned earlier, is calculated as follows: fnorm \u003d L / 200, where L- the span length, and 200 - the allowable distance in centimeters for each unit of subsidence of the timber. For reinforced concrete beam, distributed load q to which 400 kg / m 2 is usually equated, the calculation of the limiting bending moment is performed according to the formula M max \u003d (q · L 2) / 8. In this case, the number of reinforcement and its weight is determined according to the following table:

Cross-sectional areas and masses of reinforcing bars

Diameter, mm	Cross-sectional area, cm 2, with the number of rods									Weight 1 linear m, kg	Diameter, mm
Wire and bar fittings
Seven-wire ropes class K-7

The load on any beam of sufficiently homogeneous material is calculated using a number of formulas. To begin with, the moment of resistance W ≥ M / R is calculated. Here M is the maximum bending moment of the applied load, and R- design resistance, which is taken from reference books, depending on the material used. Since beams are most often rectangular in shape, the moment of resistance can be calculated differently: W z \u003d b h 2 / 6, where b is the width of the beam, and h- height.

What else you should know about beam loads

The ceiling, as a rule, is at the same time the floor of the next floor and the ceiling of the previous one. So, you need to make it so that there is no risk of combining the upper and lower rooms by simply overloading the furniture. Especially such a probability arises when the step between the beams is too large and the lags are abandoned (plank floors are laid directly on the timber laid in the spans). In this case, the distance between the crossbars directly depends on the thickness of the boards, for example, if it is 28 millimeters, then the length of the board should not be more than 50 centimeters. In the presence of lags, the minimum gap between the beams can reach 1 meter.

You should also take into account the mass used for the floor. For example, if mineral wool mats are laid, then a square meter of the basement will weigh from 90 to 120 kilograms, depending on the thickness of the thermal insulation. Sawdust concrete will double the mass of the same area. The use of expanded clay will make the floor even harder, since the load per square meter will be 3 times more than when laying mineral wool. Further, we should not forget about the payload, which for interfloor ceilings is 150 kilograms per square meter minimum. In the attic, it is enough to accept an allowable load of 75 kilograms per square.

Today, a variety of materials are used for construction, but wooden beams are most often in demand. They are used for the construction of the truss system, for the organization of floors of attics, basements and between floors. It is wooden structures that are used in the construction of the floor along the logs. This material is durable, able to withstand numerous loads, environmentally friendly and relatively low cost. If a wooden beam is used, it is necessary to first carry out calculations regarding their length. If there is no experience, then it is better to entrust the work to specialists.

Loads on wooden structures

If floor beams are used, it should be taken into account what load will be in general. This takes into account:

• own weight of a wooden beam;
• weight from inter-beam filling, i.e. insulation, waterproofing and other things;
• sheathing.

The calculation is carried out taking into account what kind of insulation is used, what step of the beams is taken (the amount of material depends on this). The issue of insulation should be taken seriously. A cold attic will lead to higher heating costs, which is approximately 15% of additional costs. To insulate the attic, you can purchase fiberglass or basalt slabs. They are relatively lightweight and install quickly.

The weight from furniture, equipment and people is taken into account. Usually the value is taken as an average of 50 kg / m² for hemming and inter-beam filler. The operational load according to SNiP 2.01.07-85 for overlapping in this case will be equal to:

70 * 1.3 = 90 kg / m², while

"70" is the standard, and 1.3 is the so-called safety factor.

The total value is:

50 + 90 = 130 kg/m².

The value should be rounded up, the figure is 150. If heavy material is purchased for insulation, then the total value will be different. It will be 245 or 250 kg / m².

50 + 1.3 * 150, where 150 kg / m² is the standard value.

If the attic is used as living space, then the calculated load level rises to 350 kg / m².

This should not be forgotten, otherwise the design will not turn out as strong as it is necessary. For ordinary interfloor, a standard value of 350-400 kg / m² is used.

Cross section and other parameters

To measure the cross section of timber beams, data such as:

Table 1. Choice of section of truss systems.

• product length for the overlapping device - L;
• product height - h;
• beam width - s.

For construction work, it is recommended to use products of rectangular section, while the height and width should be in a ratio of 1.4: 1. The optimal height should be 100-300 mm, and the width - 40-200 mm (depending on the purpose of laying the material). When choosing a height, it is necessary to focus on what kind of heat insulator will be bought, since after laying it should go flush with the surface, not form cavities and gaps after sewing.

If logs are used for work, then it is best to take the diameter equal to 110-300 mm - this is the most optimal size. When constructing a floor made of wooden beams, attention should be paid to what the laying step will be. It can be equal to 30-120 cm, it all depends on the features of the future structure and the expected loads. Often the step is chosen based on what the insulation will be. To build a house using frame technology, it must be equal to the used step of the racks. For example, if the vertical racks of the walls are mounted in increments of 60 cm, then the distance between the lags is made equal to 60 cm.

How is the data calculated? There are specially developed standards, according to which any calculation is carried out. Using them, it must be remembered that the deflection for an interfloor ceiling can be 1/350, and for an attic - 1/200 of the length of the product.

Table 2. Permissible sections of beams of interfloor and attic floors, depending on the span at a load of 400 kg per 1 m2.

For example, when a calculation is carried out taking into account the beam section, the following steps and span lengths are observed:

• section of a wooden beam 75 * 100 mm, step - 60 cm, span - 200 cm;
• 75*150 mm, step - 100 cm, span - 200 cm;
• 75*200 mm, span - 200 cm, etc.

Such data are used when an interfloor floor is being constructed with a planned load of 400 kg / m². If it is at the level of 150-350 kg / m² for the attic (less often interfloor) floor, then you need to take the following data:

• load 150 kg/m², span 300 cm, beam section 50*140 mm;
• 200 kg / m², span - 300 cm, beam section 50 * 160 mm, etc.

These data are shown in table 1.

If logs will be used for the construction of the floor, then the data indicated in table 2 (with a weight of 400 kg / m²) are used for the calculation. When using the given data for calculation, it must be remembered that the products should be taken whole, without defects, including cracks, rot, falling knots.

When using wooden beams for construction, utmost attention should be paid to calculations. This concerns the calculation of the section and the step of the overlap, corresponding to its length of the span. It is necessary to immediately carry out all the calculations, do not forget that for attic, basement and interfloor structures, the loads will be completely different.

Wooden floor beams are often the most economical option when building a private country house. At the same time, it should be noted that wooden beams are easy to manufacture and easy to install, have low thermal conductivity compared to steel or reinforced concrete structures. The main disadvantage of wooden beams is low mechanical strength, requiring large sections, as well as low resistance to damage by microorganisms and woodworms and combustibility. Therefore, wooden floor beams must be carefully calculated for the required load and treated with antiseptic and fire retardant agents.
Beams are led into the wall by at least 120 mm and waterproofing is arranged around the perimeter, except for the end. In addition, it is desirable to fix the beam with an anchor embedded in the wall.
The cross section of the beam and the step of laying the beams is calculated when designing the house, depending on the width of the overlapped span. If there is no such project, then the beam section is chosen larger, and the step of laying the beams is smaller. The best section for a wooden beam is rectangular with a width to height ratio of 1: 1.4. So with a beam width of 150 mm, its height should be about 210 mm. It should be noted that the optimal span for wooden beams is in the range of 2.5-4.0 meters. Floor beams are laid along a short section of the span. It is recommended to choose the installation step of the wooden beams of the frame structure equal to the installation step of the frame racks.
When choosing a section of a wooden beam, the load of the own weight of the floor is taken into account, which for beams of interfloor floors, as a rule, is 190-220 kg / m 2, and the load is temporary (operational), the value of which is taken equal to 200 kg / m 2. Therefore, it is recommended to calculate the cross section of wooden beams for a floor load of 400 kg / m 2.
You can determine the cross section of wooden floor beams at a load of 400 kg / m 2, depending on the span length and installation step, according to table 1.

Table 1. Optimum sections of wooden floor beams at a load of 400 kg / m 2.

installation step,	Span length, m

If, during the construction of an interfloor or attic floor, heat and sound insulation are not planned, and also if this is a floor with an unused attic, then for lower load values, it is possible to determine the minimum cross-sectional dimensions of wooden floor beams from Table 2.

Table 2. Minimum sections of wooden floor beams for loads from 150 to 350 kg / m 2.

Cross-section of beams with span length, m

In conclusion, it can be noted that the installation step of the floor beams for this structure is optimal, and the cross section must be determined from the tables.
If the section of the wooden floor beams is not enough, it is not enough time for the floor to walk, additional supports should be installed under the floor beams. This may be in the form of a cross beam supported by walls or columns.
If the installation of an additional support under the floor beams on the lower floor is not desirable, then you can install a transverse beam on top of the floor beams and fasten it to them, and if possible, to the central run of the truss system. This will redistribute the load between the beams.
There is another option to eliminate the deflection of the beams - to reduce the step of their laying.

Added: 05/25/2012 09:14

Forum discussion:

At my dacha, they made the overlap of the 2nd floor. The logs were laid (beam 150 * 150mm, step 500mm), plywood nailed on top = 10mm thick. In some places, the overlap walks: up and down. Tell me, please, did I take the step of the beam correctly and how can I strengthen the structure?